An electric dipole is placed at rest in a uniform external electric field,and released.Discuss its motion mathematically.


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Question Number 40770 by Necxx last updated on 27/Jul/18

$A n e l e c t r i c d i p o l e i s p l a c e d a t r e s t$ $i n a u n i f o r m e x t e r n a l e l e c t r i c$ $f i e l d, a n d r e l e a s e d . D i s c u s s i t s$ $m o t i o n m a t h e m a t i c a l l y .$
	Answered by tanmay.chaudhury50@gmail.com last updated on 27/Jul/18

	$l e t a n g l e b e t w e e n a x i s o f d i p o l e a n d e l e c t r i c$ $f i e l d i s θ$ $l e n g t h o g d i p o l e = 2 l c h a r g e o n e a c h p o l e a r e$ $+ q a n d - q e x t e r n a l e l e c t r i c f i e l d = E$ $s o n e t f o r c e o n d i p o l e = q E + (- q) E = 0$ $T o r q u e w i t h r e s p e c t t o c e n t r e o f d i p o l e i s$ $\vec{⌈} = \vec{l} \times q \vec{E} + (- \vec{l}) \times (- q \vec{E})$ $= 2 q \vec{l} \times \vec{E}$ $⌈ = 2 q l E s i n θ$
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