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Question Number 180157 by Tawa11 last updated on 08/Nov/22

As the force on a string increases from 100N to 180N, the string extends by 10cm. The work done in increasing the tension in the string is?

Answered by DvMc last updated on 08/Nov/22

$$W=F\times d$$$$W=(180N-100N)\times 0.1m=8Nm$$

Answered by mr W last updated on 08/Nov/22

$$W=\int Fds=\frac{100+180}{2}\times 0.1=14J$$$$or$$$$k=\frac{180-100}{0.1}=800N/m$$$$W=E_2-E_1=\frac{k(s_2^2-s_1^2)}{2}$$$$=\frac{k}{2}[{\left(\frac{F_2}{k}\right)}^2-{\left(\frac{F_1}{k}\right)}^2]=\frac{F_2^2-F_1^2}{2k}$$$$=\frac{{180}^2-{100}^2}{2\times 800}=14J$$

Commented by Tawa11 last updated on 08/Nov/22

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir},\mathrm{I}\mathrm{appreciate}.$$

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