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Question Number 104367 by Study last updated on 21/Jul/20

$${CH}_3-{CH}_2-{CH}_2-{CH}_{2}Cl+KOH\to$$$$helpme$$

Answered by 1549442205PVT last updated on 21/Jul/20

$${\mathit{C}\mathit{H}}_3-{\mathit{C}\mathit{H}}_2-{\mathit{C}\mathit{H}}_2-{\mathit{C}\mathit{H}}_2\mathit{C}\mathit{l}+\mathit{K}\mathit{O}\mathit{H}$$$$\to \mathbf{KCl}+{\mathbf{H}}_2\mathbf{O}+{\mathbf{CH}}_3-\mathbf{CH}=\mathbf{CH}-{\mathbf{CH}}_3$$

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