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Question Number 151061 by qaz last updated on 18/Aug/21

Calculate  :: ∫_0 ^(π/2) x∙cot x∙ln^2 cos xdx=(π^3 /(24))ln2+(π/6)ln^3 2−(3/(16))πζ(3)

Calculate::0π/2xcotxln2cosxdx=π324ln2+π6ln32316πζ(3)

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