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Question Number 151067 by qaz last updated on 18/Aug/21

$$\mathrm{Calculate}::{\int }_0^{\pi }\sin \frac{\mathrm{x}}{2}\cdot \arctan (\frac{2}{\sin \mathrm{x}}-1)\mathrm{dx}=\sqrt{2}\ln (1+\sqrt{2})+(1-\frac{1}{\sqrt{2}})\pi$$

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