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Question Number 151068 by qaz last updated on 18/Aug/21

$$\mathrm{Calculate}::{\int }_0^{\mathrm{\infty }}\frac{\sqrt{\mathrm{x}}}{{({\mathrm{x}}^4+{14\mathrm{x}}^2+1)}^{\frac{5}{4}}}\mathrm{dx}=\frac{{\mathrm{\Gamma }}^2\left(\frac{3}{4}\right)}{4\sqrt{2\pi }}$$

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