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Question Number 167970 by qaz last updated on 30/Mar/22

$$\mathrm{Calculate}:\underset{\mathrm{n}\to \mathrm{\infty }}{\lim }\underset{\mathrm{k}=1}{\sum ^{\mathrm{n}}}\frac{{\mathrm{k}}^2}{{\mathrm{n}}^3}\cdot \sqrt[\mathrm{k}]{\mathrm{k}}=?$$

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