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Question Number 18922 by Tinkutara last updated on 01/Aug/17

$$\mathrm{Consider}\mathrm{a}\mathrm{block}\mathrm{sliding}\mathrm{over}\mathrm{a}\mathrm{smooth}$$$$\mathrm{inclined}\mathrm{surface}\mathrm{of}\mathrm{inclination}\theta .\mathrm{Relating}$$$$\mathrm{to}{\mathrm{Newton}}^{\prime }\mathrm{s}\mathrm{second}\mathrm{law}\mathrm{applied}\mathrm{on}\mathrm{the}$$$$\mathrm{block},\mathrm{select}\mathrm{the}\mathrm{incorrect}\mathrm{alternative}.$$$$\left(1\right)\mathrm{\Sigma }{F}_{y^{\prime }}\ne 0$$$$\left(2\right)\mathrm{\Sigma }{F}_y=0$$$$\left(3\right)\mathrm{\Sigma }{F}_x=-mg\sin \theta$$$$\left(4\right)\mathrm{\Sigma }{F}_{x^{\prime }}<0$$

Commented by Tinkutara last updated on 01/Aug/17

Commented by Tinkutara last updated on 01/Aug/17

$$\mathrm{Thank}\mathrm{you}\mathrm{very}\mathrm{much}\mathrm{ajfour}\mathrm{Sir}!$$

Commented by ajfour last updated on 01/Aug/17

$$\mathrm{\Sigma }{\mathrm{F}}_{\mathrm{x}}=\mathrm{mgsin}\theta$$

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