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Coordinate GeometryQuestion and Answers: Page 4

Question Number 199769 Answers: 0 Comments: 0

62n7z7

$62 n 7 z 7$

Question Number 199766 Answers: 1 Comments: 0

Question Number 199688 Answers: 4 Comments: 1

Question Number 199351 Answers: 1 Comments: 0

Question Number 199101 Answers: 3 Comments: 0

Question Number 199625 Answers: 1 Comments: 0

Given Fibonacci series F_1 =F_2 = 1 and F_(n+2) = F_(n+1) +F_n for n>0. Find the remainder F_(2022) divides by 5

$Given Fibonacci series$ $F_{1} = F_{2} = 1 and F_{n + 2} = F_{n + 1} + F_{n}$ $for n > 0 . Find the remainder$ $F_{2022} divides by 5$

Question Number 198434 Answers: 1 Comments: 1

Question Number 198210 Answers: 1 Comments: 1

Red Area?

$Red Area ?$

Question Number 198207 Answers: 1 Comments: 1

((yellow Area)/(Squart Area))=?

$\frac{yellow Area}{Squart Area} = ?$

Question Number 198059 Answers: 1 Comments: 1

Montrer l egalite (voir la figure )

$Montrer l egalite (voir la figure)$

Question Number 197740 Answers: 3 Comments: 0

Question Number 197730 Answers: 2 Comments: 3

Question Number 197359 Answers: 2 Comments: 1

lim_(x→0) ((1−cosxcos2x...cos(nx))/x^2 ) = ((n(n+1)(2n+1))/(12))

$\lim_{x \to 0} \frac{1 - c o s x c o s 2 x . . . c o s (n x)}{x^{2}} = \frac{n (n + 1) (2 n + 1)}{12}$

Question Number 196992 Answers: 0 Comments: 0

If A(a^2 , 2a), B((1/a^2 ), ((− 2)/a)) and S(1, 0) are three points then prove that, (1/(SA)) + (1/(SB)) = 1.

$If A (a^{2}, 2 a), B (\frac{1}{a^{2}}, \frac{- 2}{a}) and S (1, 0)$ $are three points then prove that,$ $\frac{1}{SA} + \frac{1}{SB} = 1 .$

Question Number 196917 Answers: 3 Comments: 0

Question Number 196674 Answers: 0 Comments: 0

prove that lim_(n→+∞) (−1)^(n−1) +Σ_(p=2) ^n (−1)^p pln(((p+1)/(p−1)))=ln(π)

$prove that$ $\lim_{n \to + \infty} {(- 1)}^{n - 1} + \underset{p = 2}{\sum^{n}} {(- 1)}^{p} pln (\frac{p + 1}{p - 1}) = \ln (π)$

Question Number 197585 Answers: 4 Comments: 0

f (x)=f((1/x)) ⇒ f(x)=?

$f (x) = f (\frac{1}{x})$ $\Rightarrow f (x) = ?$

Question Number 196460 Answers: 1 Comments: 5

Question Number 196395 Answers: 0 Comments: 1

Question Number 196321 Answers: 1 Comments: 0

lim_(n→+∞) sin(2π(√(n^2 +1 )) ) = 0 lim_(n→+∞) arg(n^2 +n+1+i) = 0

$\lim_{n \to + \infty} s i n (2 π \sqrt{n^{2} + 1}) = 0$ $\lim_{n \to + \infty} a r g (n^{2} + n + 1 + i) = 0$

Question Number 196304 Answers: 3 Comments: 0

Question Number 194821 Answers: 0 Comments: 2

M a inside poin in ΔABC. M = bar {(A, area(MBC)), (B, area(MAC)),(C,area(MAB))}

$M a i n s i d e p o i n i n Δ A B C .$ $M = b a r {(A, a r e a (M B C)), (B, a r e a (M A C)), (C, a r e a (M A B))}$

Question Number 194301 Answers: 1 Comments: 0

Resolution de l exercice du 28.6.23 (envoye par universe ) Q194116

$Resolution de l exercice du 28.6.23$ $(e n v o y e p a r u n i v e r s e)$ $Q 194116$

Question Number 194131 Answers: 1 Comments: 1

Question Number 193951 Answers: 2 Comments: 0

Prove that: lim_(n→+∞) (1/(n!))∫^( n) _( 0) t^n e^(−t) dt = (1/2)

$Prove that :$ $\lim_{n \to + \infty} \frac{1}{n!} {\int_{0}}^{n} t^{n} e^{- t} d t = \frac{1}{2}$

Question Number 193235 Answers: 1 Comments: 0

Pg 1 Pg 2 Pg 3 Pg 4 Pg 5 Pg 6 Pg 7 Pg 8 Pg 9 Pg 10

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