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Question Number 122648 by mathocean1 last updated on 18/Nov/20

Determinate the values of n ∈ N such that n−1 can divise 2n+3

Determinatethevaluesofn∈Nsuchthatn−1candivise2n+3

Answered by TANMAY PANACEA last updated on 18/Nov/20

2n−2+5 when devided by n−1 2+(5/(n−1)) n should be 6

2n−2+5whendevidedbyn−12+5n−1nshouldbe6

Commented by mathocean1 last updated on 18/Nov/20

thank you sir

thankyousir

Answered by MJS_new last updated on 18/Nov/20

2n+3=k(n−1) k=2+(5/(n−1)) ⇒ for n∈Z: n−1∣5 ⇒ n∈{−4, 0, 2, 6} but n∈N ⇒ n∈{0, 2, 6}

2n+3=k(n−1)k=2+5n−1⇒forn∈Z:n−1∣5⇒n∈{−4,0,2,6}butn∈N⇒n∈{0,2,6}

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