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DifferentiationQuestion and Answers: Page 12

Question Number 162804    Answers: 2   Comments: 0

Ω = ∫ sin^( 2) (x).cos^( 4) (x ) dx

Ω=sin2(x).cos4(x)dx

Question Number 162701    Answers: 1   Comments: 0

Question Number 162675    Answers: 1   Comments: 0

y = (√x) Find (dy/dx) by first principle.

y=xFinddydxbyfirstprinciple.

Question Number 162516    Answers: 0   Comments: 1

differenciate using implicit function 2x+4y+sin xy=3

differenciateusingimplicitfunction2x+4y+sinxy=3

Question Number 162424    Answers: 1   Comments: 0

calculate Ω = Σ_(n=1) ^∞ (( (−1)^( n) n)/(3^( n) (2n −1 ))) =? − Inspired from Sir Ghaderi′s post−

calculateΩ=n=1(1)nn3n(2n1)=?InspiredfromSirGhaderispost

Question Number 162395    Answers: 0   Comments: 1

Question Number 162377    Answers: 1   Comments: 2

prove that ψ′′ ((1/4) )= −2π^( 3) − 56 ζ (3 )

provethatψ(14)=2π356ζ(3)

Question Number 162371    Answers: 2   Comments: 0

If x ∈R the maximum value of ((3x^2 +9x+17)/(3x^2 +9x+7)) is ...

IfxRthemaximumvalueof3x2+9x+173x2+9x+7is...

Question Number 162336    Answers: 1   Comments: 0

lim_( n→∞) ((1/(1+n^( 3) )) +(( 4)/(8 +n^( 3) )) + (9/(27 +n^( 3) )) +...+(n^( 2) /(2n^( 3) )) )=?

limn(11+n3+48+n3+927+n3+...+n22n3)=?

Question Number 162168    Answers: 0   Comments: 0

Solve the integro−differential equation: i(t) + 4(di/dt) + ∫i(t)dt = 2 cos (3t+ 60°) where i(t) is a sinulsodial current.

Solvetheintegrodifferentialequation:i(t)+4didt+i(t)dt=2cos(3t+60°)wherei(t)isasinulsodialcurrent.

Question Number 162025    Answers: 0   Comments: 0

write the taylor expansion of : f(x)= x^( 2) . cos(x) at x=1 then f^( (5 )) (x) at x=1 ?

writethetaylorexpansionof:f(x)=x2.cos(x)atx=1thenf(5)(x)atx=1?

Question Number 162026    Answers: 2   Comments: 0

prove that.... ( 1+ (1/n) )^( n) < e < (1+(1/n) )^( n+1)

provethat....(1+1n)n<e<(1+1n)n+1

Question Number 161875    Answers: 0   Comments: 0

Question Number 161802    Answers: 1   Comments: 0

Question Number 161750    Answers: 0   Comments: 2

differenciate xsin xcos x

differenciatexsinxcosx

Question Number 161406    Answers: 0   Comments: 0

f (x ) = cos^( 2) ( x ) + sin^( 4) ( x ) R_( f) = ? −−−solution−−− y = cos^( 2) (x ) + sin^( 2) (x) .( 1−cos^( 2) (x)) = 1 − (1/4) sin^( 2) ( 2x) we know that : 0≤ sin^( 2) ( αx) ≤1 therefore −1≤− sin^( 2) (2x) ≤ 0 1−(1/4) ≤ 1− (1/4) sin^( 2) (2x) ≤1 R_( f) = [ (3/4) , 1 ] ◂ ★ ▶

f(x)=cos2(x)+sin4(x)Rf=?solutiony=cos2(x)+sin2(x).(1cos2(x))=114sin2(2x)weknowthat:0sin2(αx)1therefore1sin2(2x)0114114sin2(2x)1Rf=[34,1]

Question Number 161369    Answers: 2   Comments: 0

Determine the value of the following proposition . ( True or False ) ∃ x ∈ R ; determinant ((( 1+2x),( 2x),(2x)),(( 2x),( 1+2x),( 2x )),(( 2x),( 2x),(1 +2x)))= x^( 3) + 8x−2 −−−−−−−−−

Determinethevalueofthefollowingproposition.(TrueorFalse)xR;|1+2x2x2x2x1+2x2x2x2x1+2x|=x3+8x2

Question Number 161311    Answers: 2   Comments: 0

Differentiate y=sin xy

Differentiatey=sinxy

Question Number 161209    Answers: 0   Comments: 1

Differentiate y=e^(−x^2 )

Differentiatey=ex2

Question Number 161136    Answers: 2   Comments: 0

≺ X , τ ≻ is a topological space and A ⊆ X , A^− =^? ∩_(F⊃A) F ( F is closed set )

X,τisatopologicalspaceandAX,A=?FAF(Fisclosedset)

Question Number 161130    Answers: 1   Comments: 0

Given P(x) is polynomial such that P(3x)= P ′(x).P ′′(x) . Find the tangent of curve y = P(x) parallel to the line y= 4x−2.

GivenP(x)ispolynomialsuchthatP(3x)=P(x).P(x).Findthetangentofcurvey=P(x)paralleltotheliney=4x2.

Question Number 160968    Answers: 1   Comments: 0

Question Number 160967    Answers: 0   Comments: 0

Question Number 160933    Answers: 1   Comments: 0

In the given equation below , applying the formula for the derivative of inverse trigonometric functions , what is the ′′u ′′ from the given function. y = cosec^(−1) [ sin (((1+sin x)/(cos x)))]

Inthegivenequationbelow,applyingtheformulaforthederivativeofinversetrigonometricfunctions,whatistheufromthegivenfunction.y=cosec1[sin(1+sinxcosx)]

Question Number 160837    Answers: 0   Comments: 4

Question Number 160822    Answers: 0   Comments: 0

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