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1. f(x)= { ((sinx , (π/2)<x≤2π)),((cosx , 0≤x≤(π/2))) :} then find the f^′ ((π/2)) =? 2. f(x)= { ((sinx , (π/2)<x≤2π)),((cosx , 0≤x≤(π/2))) :} then find the f′(2π) =?

$1 . f (x) = {\begin{cases} sinx, \frac{π}{2} < x ⩽ 2 π \\ cosx, 0 ⩽ x ⩽ \frac{π}{2} \end{cases}$ $then find the f^{^{'}} (\frac{π}{2}) = ?$ $2 . f (x) = {\begin{cases} sinx, \frac{π}{2} < x ⩽ 2 π \\ cosx, 0 ⩽ x ⩽ \frac{π}{2} \end{cases}$ $then find the f^{'} (2 π) = ?$

Question Number 195170 Answers: 2 Comments: 0

f(x)= { ((x^7 +2x+1 ;x≥2)),((x^2 +7x+4 ;x<1)) :} f^′ (1)=?

$f (x) = {\begin{cases} x^{7} + 2 x + 1; x ⩾ 2 \\ x^{2} + 7 x + 4; x < 1 \end{cases}$ $f^{^{'}} (1) = ?$

Question Number 195137 Answers: 1 Comments: 0

f(x)=arctan(((4sinx)/(3+5cosx))) then f^′ ((π/3))=?

$f (x) = a r c t a n (\frac{4 s i n x}{3 + 5 c o s x}) t h e n f^{^{'}} (\frac{π}{3}) = ?$

Question Number 194852 Answers: 1 Comments: 0

lim_(x→0) (cosx)^(log(x)) =?

$\lim_{x \to 0} {(cosx)}^{\log (x)} = ?$

Question Number 194467 Answers: 2 Comments: 0

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$\underset{―}{⇊}$

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$X$

Question Number 194211 Answers: 1 Comments: 0

(1/x^2 ) +(1/y^2 ) = (1/3) (d^2 y/dx^2 ) =?

$\frac{1}{x^{2}} + \frac{1}{y^{2}} = \frac{1}{3}$ $\frac{d^{2} y}{{dx}^{2}} = ?$

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f(x) = 2+∫_0 ^( x) (2t+f(t))^2 dt then ∫_(−1) ^2 f(x) dx =

$f (x) = 2 + \underset{0}{\int^{x}} {(2 t + f (t))}^{2} dt$ $then \underset{- 1}{\int^{2}} f (x) dx =$

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find the value of the following integral χ = ∫_0 ^( ∞) (( ln^( 2) (x ))/(1+ x^( 2) )) dx = ? −−−−−−−−−

$f i n d t h e v a l u e o f t h e f o l l o w i n g i n t e g r a l$ $χ = \int_{0}^{\infty} \frac{\ln^{2} (x)}{1 + x^{2}} d x = ?$ $- - - - - - - - -$

Question Number 192343 Answers: 1 Comments: 0

Find minimum value of y=((1−sin^2 x)/(2 tan^2 x))

$Find minimum value of$ $y = \frac{1 - \sin^{2} x}{2 \tan^{2} x}$

Question Number 192289 Answers: 1 Comments: 0

∫_(−e) ^e ((sin x)/(sec^2 x+1)) dx =?

$\underset{- e}{\int^{e}} \frac{\sin x}{\sec^{2} x + 1} dx = ?$

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