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Question Number 218162 by Ismoiljon_008 last updated on 31/Mar/25

        Each edge of a parallelepiped is 1 cm long.     At one of its vertices, all three face angles     are acute, and each measures 2α.     Find the volume of the parallepiped.     Help me,  please

Eachedgeofaparallelepipedis1cmlong.Atoneofitsvertices,allthreefaceanglesareacute,andeachmeasures2α.Findthevolumeoftheparallepiped.Helpme,please

Answered by mr W last updated on 31/Mar/25

Commented by mr W last updated on 31/Mar/25

a=b=c=1  base area A_(Base) =ab sin 2α=sin 2α  h=(√(1^2 −(((1×cos 2α)/(cos α)))^2 ))=(√(1−((cos^2  2α)/(cos^2  α))))  V=A_(Base) h=sin 2α(√(1−((cos^2  2α)/(cos^2  α))))=2 sin^2  α

a=b=c=1baseareaABase=absin2α=sin2αh=12(1×cos2αcosα)2=1cos22αcos2αV=ABaseh=sin2α1cos22αcos2α=2sin2α

Commented by Ismoiljon_008 last updated on 31/Mar/25

   Thank you very much

Thankyouverymuch

Commented by Ismoiljon_008 last updated on 31/Mar/25

   Mr W,  why is the length of AD equal     to  ((1∙cos2α)/(cosα))  ?

MrW,whyisthelengthofADequalto1cos2αcosα?

Commented by mr W last updated on 31/Mar/25

AC=AB cos 2α=1×cos 2α  AD=((AC)/(cos α))=((1×cos 2α)/(cos α))

AC=ABcos2α=1×cos2αAD=ACcosα=1×cos2αcosα

Commented by Ismoiljon_008 last updated on 31/Mar/25

   I got it. Thank you Mr W

Igotit.ThankyouMrW

Commented by mr W last updated on 31/Mar/25

the general formula:

thegeneralformula:

Commented by mr W last updated on 31/Mar/25

Commented by Ismoiljon_008 last updated on 01/Apr/25

   Thanks

Thanks

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