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Question Number 191536 by MATHEMATICSAM last updated on 25/Apr/23

Factorize (2/(2x − 1)) −5 + (3/(3x − 1))

Factorize22x−1−5+33x−1

Answered by som(math1967) last updated on 25/Apr/23

(2/(2x−1))−3+(3/(3x−1))−2 =((2−6x+3)/(2x−1)) +((3−6x+2)/(3x−1)) =(5−6x)((1/(2x−1)) +(1/(3x−1)))

22x−1−3+33x−1−2=2−6x+32x−1+3−6x+23x−1=(5−6x)(12x−1+13x−1)

Answered by Frix last updated on 25/Apr/23

−(((5x−2)(6x−5))/((2x−1)(3x−1)))

−(5x−2)(6x−5)(2x−1)(3x−1)

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