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Question Number 217040 by ArshadS last updated on 27/Feb/25

$$\mathrm{Find}\mathrm{all}\mathrm{positive}\mathrm{integers}\mathrm{n}\mathrm{such}\mathrm{that}$$$$\mathrm{n}\mathrm{divides}{2}^n+1.$$

Answered by Ghisom last updated on 27/Feb/25

$$\mathrm{one}\mathrm{group}\mathrm{of}\mathrm{solutions}\mathrm{is}n=3^k\wedge k\in \mathbb{N}$$$$\mathrm{but}\mathrm{there}\mathrm{are}\mathrm{other}$$$$n=3^{2}19\times 3^k\mathrm{also}\mathrm{seems}\mathrm{to}\mathrm{fit}$$$$...$$

Answered by mehdee7396 last updated on 28/Feb/25

$$n=3^k$$$$$$

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