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Question Number 180211 by Shrinava last updated on 09/Nov/22

$$\mathrm{Find}:$$$$\mathrm{\Omega }=\gcd (4^{2020}-1,8^{2021}-1).\mathrm{Generalization}.$$

Answered by puissant last updated on 09/Nov/22

$$\mathrm{\Omega }=gcd(2^{4040}-1;2^{6063}-1)$$$$=2^{gcd(4040;6063)}-1$$$$=2^1-1$$$$=1.$$

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