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Question Number 88040 by peter frank last updated on 08/Apr/20

Find the max and min  of function  ((a+bsin x)/(b+asin x))  where b>a>0 in the   interval 0≤x≤2π.sketch  a=4 and b=5

Findthemaxandminoffunctiona+bsinxb+asinxwhereb>a>0intheinterval0x2π.sketcha=4andb=5

Commented by john santu last updated on 08/Apr/20

f(x) = ((bsin x+a)/(asin x+b))  f′(x) = (((b^2 −a^2 )cos x)/((asin x+b)^2 )) = 0  (b^2 −a^2 ) ≠0 , then cos x = 0  cos x = 0  { ((x_1 =(π/2))),((x _2 = ((3π)/2))) :}  f(x_1 ) = ((b+a)/(a+b)) = 1 ←max  f(x_2 ) = ((a−b)/(b−a)) = −1 ←min

f(x)=bsinx+aasinx+bf(x)=(b2a2)cosx(asinx+b)2=0(b2a2)0,thencosx=0cosx=0{x1=π2x2=3π2f(x1)=b+aa+b=1maxf(x2)=abba=1min

Commented by peter frank last updated on 15/Apr/20

thank you

thankyou

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