Find the number of six−digit odd numbers without repeated digits.


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Question Number 101880 by mr W last updated on 05/Jul/20

$F i n d t h e n u m b e r o f s i x - d i g i t o d d$ $n u m b e r s w i t h o u t r e p e a t e d d i g i t s .$
	Answered by bemath last updated on 05/Jul/20

	$5 \times 8 \times C_{4}^{8} \times 4!$
	Commented by mr W last updated on 05/Jul/20

	$c o r r e c t, t h a n k s!$
	Answered by som(math1967) last updated on 05/Jul/20

	$Odd numbers unitdigit 1$ ${\overset{9}{p}}_{5} - \overset{8}{} p_{4} = 9 \times 8 \times 7 \times 6 \times 5 - 8 \times 7 \times 6 \times 5$ $= 8 \times 7 \times 6 \times 5 (9 - 1)$ $= 8 \times 7 \times 6 \times 40$ $∴ total odd numbers = 56 \times 240 \times 5$ $= 67200$
	Commented by som(math1967) last updated on 05/Jul/20

	$welcome sir$
	Commented by mr W last updated on 05/Jul/20

	$c o r r e c t, t h a n k s!$
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