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Question Number 10070 by Tawakalitu ayo mi last updated on 23/Jan/17

$$\mathrm{Find}\mathrm{the}\mathrm{sum}\mathrm{of}\mathrm{the}\mathrm{digits}\mathrm{of},$$$${3333333334}^2$$

Answered by ridwan balatif last updated on 23/Jan/17

$$3^2=9$$$${33}^2=1089$$$${333}^2=110889$$$${3333}^2=11108889$$$$.$$$$.$$$$.$$$$.$$$${3333333333}^2=11111111108888888889$$$$$$$${3333333334}^2={(3333333333+1)}^2$$$$={3333333333}^2+2\times 3333333333+1^2$$$$=11111111115555555556$$$$\mathrm{the}\mathrm{sum}\mathrm{of}\mathrm{digit}=1\times 9+5\times 9+6=60$$

Commented by Tawakalitu ayo mi last updated on 23/Jan/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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