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Question Number 21241 by tawa tawa last updated on 17/Sep/17
Findyin3rdquadranttan(y−30)=cot(y)
Answered by sma3l2996 last updated on 17/Sep/17
tan(y−30)=cot(y)tan(y−30)=1tan(y)⇔tan(y)−tan(30)1+tan(y)tan(30)=1tanywithtan(30)=33tan(y)(tan(y)−tan(30))=1+tan(y)tan(30)tan2(y)−33tan(y)−33tan(y)=1tan2(y)−233tan(y)−1=0Δ=43+4=163=(433)2tan(y)=233−4332=−33⇔y=−π6+kπortan(y)=233+4332=3⇔y=π3+kπ
Commented by tawa tawa last updated on 17/Sep/17
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