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GeometryQuestion and Answers: Page 24

Question Number 191832    Answers: 0   Comments: 0

Question Number 191577    Answers: 0   Comments: 0

Give A′B′//AB, B′C′//BC and A′C′//AC Prove that: △ABC∽△A′B′C′

GiveAB//AB,BC//BCandAC//ACProvethat:ABCABC

Question Number 191602    Answers: 1   Comments: 1

Question Number 191455    Answers: 2   Comments: 0

Question Number 191405    Answers: 0   Comments: 3

Question Number 191404    Answers: 1   Comments: 0

Question Number 191403    Answers: 1   Comments: 0

Question Number 191396    Answers: 0   Comments: 0

Question Number 191310    Answers: 1   Comments: 0

Question Number 191212    Answers: 0   Comments: 0

Question Number 191205    Answers: 1   Comments: 2

Question Number 191192    Answers: 1   Comments: 1

Question Number 191060    Answers: 1   Comments: 0

Question Number 190890    Answers: 0   Comments: 1

Question Number 190856    Answers: 0   Comments: 0

Give M is any point in ABC triangle Prove that: MA+MB+MC<AC+BC

GiveMisanypointinABCtriangleProvethat:MA+MB+MC<AC+BC

Question Number 190745    Answers: 0   Comments: 0

Give M is any point in ABC triangle. Prove that MA+MB+MC<AC+BC

GiveMisanypointinABCtriangle.ProvethatMA+MB+MC<AC+BC

Question Number 190615    Answers: 1   Comments: 1

Question Number 190644    Answers: 1   Comments: 0

Question Number 190565    Answers: 1   Comments: 0

Question Number 190340    Answers: 3   Comments: 4

Question Number 190269    Answers: 1   Comments: 1

Question Number 190242    Answers: 0   Comments: 0

Question Number 190191    Answers: 1   Comments: 0

Question Number 190104    Answers: 1   Comments: 0

In AB^Δ C : II_( a) ^( 2) =^? 4R ( r_( a) − r ) I : incircle center I_( a) : excircle center corresponding A R: circumcircle radius r: incircle radius r_( a) : excircle radius corresponding A

InABCΔ:IIa2=?4R(rar)I:incirclecenterIa:excirclecentercorrespondingAR:circumcircleradiusr:incircleradiusra:excircleradiuscorrespondingA

Question Number 190100    Answers: 1   Comments: 1

Question Number 190095    Answers: 1   Comments: 0

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