Question and Answers Forum |
GeometryQuestion and Answers: Page 90 |
![]() |
![]() |
![]() |
If the points (−3, 5) , (4, −2) and (6, 2) are the vertices of a triangle. (i) Find the equation of the perpendicular bisector of the sides (ii) Find the coordinate of the circumcenter. (The circumcenter of a triangle is the point of intersection of the perpendicular bisector of the side (iii) Find the radius of the circumcircle. |
![]() |
![]() |
![]() |
![]() |
found something (others have found before) which I thought might be of interest, especially for Sir Tanmay Chaudhury: take any polynome of degree 4 with 2 real inflection points y=ax^4 +bx^3 +cx^2 +dx+e y′′=12ax^2 +6bx+2c=0 has got 2 real solutions x_1 and x_2 the line connecting the inflection points intersects the curve in 2 more points P and Q, their x−values are p and q let p<x_1 <x_2 <q ⇒ ((x_2 −x_1 )/(x_1 −p))=((x_2 −x_1 )/(q−x_2 ))=(1/2)+((√5)/2) which is the Golden Ratio |
![]() |
![]() |
![]() |
![]() |
![]() |
Construct a triangle ΔABC with ∠B=50° AC=6 cm AB+BC=8 cm see also Q42942. |
![]() |
![]() |
![]() |
![]() |
![]() |
![]() |
![]() |
i have some thing to say...in this platform several people/students/others post questions..others take promt action to solve the problems.. after the problem got solved..the person/students who post questions never attend or see the answer even do not clarify whether the answer is right or wrong...or whether he/she got understood the method...so pls show your courtsey otherwise your problem remain a problem and nobody bother to solve it...Than you all |
![]() |
![]() |
![]() |