Question and Answers Forum

All Questions      Topic List

Mensuration Questions

Previous in All Question      Next in All Question      

Previous in Mensuration      Next in Mensuration      

Question Number 195570 by York12 last updated on 05/Aug/23

Given three Real numbers (x,y,z),such that  x^2 +y^2 +z^2 =1  maximize  x^4 +y^4 −2z^4 −3(√2)xyz

GiventhreeRealnumbers(x,y,z),suchthatx2+y2+z2=1maximizex4+y42z432xyz

Commented by Frix last updated on 05/Aug/23

I think the maximum is ((65)/(64)) when z=±((√2)/4)

Ithinkthemaximumis6564whenz=±24

Commented by York12 last updated on 05/Aug/23

please provide workings

pleaseprovideworkings

Answered by Frix last updated on 05/Aug/23

x^2 +y^2 =1−z^2  ⇒ x^4 +y^4 =−2x^2 y^2 +z^4 −2z^2 +1    x^4 +y^4 −2z^4 −3(√2)xyz=  =−2x^2 y^2 −3(√2)xyz−z^4 −2z^2 +1  Let t=xy  −2t^2 −2(√2)tz−z^4 −2z^2 +1  ((d[−2t^2 −2(√2)tz−z^4 −2z^2 +1])/dt)=0  −4t−3(√2)z=0 ⇒ t=−((3(√2)z)/4)  Inserting  −z^4 +(z^2 /4)+1  ((d[−z^4 +(z^2 /4)+1])/dz)=0  −4z^3 +(z/2)=0 ⇒ z=±((√2)/4) [∨z=0_(minimum) ^(rejected because) ]  ⇒ maximum is ((65)/(64)) ★  We have  z=((√2)/4)∧xy=−(3/8) ∨ z=−((√2)/4)∧xy=(3/8)  x^2 +y^2 =1−z^2 =(7/8)  The values are easy to calculate

x2+y2=1z2x4+y4=2x2y2+z42z2+1x4+y42z432xyz==2x2y232xyzz42z2+1Lett=xy2t222tzz42z2+1d[2t222tzz42z2+1]dt=04t32z=0t=32z4Insertingz4+z24+1d[z4+z24+1]dz=04z3+z2=0z=±24[z=0minimumrejectedbecause]maximumis6564Wehavez=24xy=38z=24xy=38x2+y2=1z2=78Thevaluesareeasytocalculate

Commented by York12 last updated on 05/Aug/23

ORZ

ORZ

Commented by York12 last updated on 05/Aug/23

where to learn inequalities   and are you using discord   I would like to invite you to our community

wheretolearninequalitiesandareyouusingdiscordIwouldliketoinviteyoutoourcommunity

Commented by Frix last updated on 05/Aug/23

Sorry I don't use any social media platforms. I studied mathematics & physics decades ago at a university, I don't know where else you could learn these things.

Commented by York12 last updated on 05/Aug/23

okay sir thanks

okaysirthanks

Commented by York12 last updated on 05/Aug/23

but if you wanted you are always welcome  we are a big community of high scholars  from different spots on the earth and we  need instructions from an efficient  person like you sir

butifyouwantedyouarealwayswelcomeweareabigcommunityofhighscholarsfromdifferentspotsontheearthandweneedinstructionsfromanefficientpersonlikeyousir

Commented by necx122 last updated on 06/Aug/23

you could share the link, a few of us are  also interested.

youcouldsharethelink,afewofusarealsointerested.

Commented by York12 last updated on 06/Aug/23

great

great

Commented by York12 last updated on 06/Aug/23

  https://discord.gg/mods

https://discord.gg/mods

Terms of Service

Privacy Policy

Contact: info@tinkutara.com