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GravitationQuestion and Answers: Page 2

Question Number 27445 Answers: 1 Comments: 0

If a planet is suddenly stopped in its orbit, supposed to be circular, then it would fall into the sun in a time (T/(4(√2))), where T is the time period of revolution. Prove this.

$I f a p l a n e t i s s u d d e n l y s t o p p e d i n i t s$ $o r b i t, s u p p o s e d t o b e c i r c u l a r, t h e n i t$ $w o u l d f a l l i n t o t h e s u n i n a t i m e \frac{T}{4 \sqrt{2}},$ $w h e r e T i s t h e t i m e p e r i o d o f$ $r e v o l u t i o n . P r o v e t h i s .$

Question Number 27287 Answers: 0 Comments: 1

Question Number 27283 Answers: 0 Comments: 0

Question Number 27074 Answers: 2 Comments: 0

Question Number 26959 Answers: 3 Comments: 0

Two balls, each of radius R, equal mass and density are placed in contact, then the force of gravitation between them is proportional to (1) F ∝ (1/R^2 ) (2) F ∝ R (3) F ∝ R^4 (4) F ∝ (1/R)

$Two balls, each of radius R, equal mass$ $and density are placed in contact, then$ $the force of gravitation between them$ $is proportional to$ $(1) F \propto \frac{1}{R^{2}}$ $(2) F \propto R$ $(3) F \propto R^{4}$ $(4) F \propto \frac{1}{R}$

Question Number 25684 Answers: 1 Comments: 0

For a geosynchronous satellite of mass m moving in a circular orbit around the earth at a constant speed v and an altitude h above the earth surface.Show the velocity v=(((GM_e )/(R_e +h)))^(1/2) . If the satellite above is synchronous how fast is it moving through space,taking the period to be 24hrs and M_e =mass of the satellite and is equal to 5.98×10^(24) kg

$F o r a g e o s y n c h r o n o u s s a t e l l i t e o f$ $m a s s m m o v i n g i n a c i r c u l a r$ $o r b i t a r o u n d t h e e a r t h a t a c o n s t a n t$ $s p e e d v a n d a n a l t i t u d e h a b o v e$ $t h e e a r t h s u r f a c e . S h o w t h e$ $v e l o c i t y v = {(\frac{{G M}_{e}}{R_{e} + h})}^{\frac{1}{2}} .$ $I f t h e s a t e l l i t e a b o v e i s s y n c h r o n o u s$ $h o w f a s t i s i t m o v i n g t h r o u g h$ $s p a c e, t a k i n g t h e p e r i o d t o b e 24 h r s$ $a n d M_{e} = m a s s o f t h e s a t e l l i t e a n d$ $i s e q u a l t o 5.98 \times 10^{24} k g$

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