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Heat and TheromdynamicsQuestion and Answers: Page 3

Question Number 42497 Answers: 0 Comments: 1

A body cools from 90°C to 40°C in 2 minutes at a temperature,20°C of the surrounding.Calculate the temperature of the body after another 5 minutes.

$A b o d y c o o l s f r o m 90 ° C t o 40 ° C i n$ $2 m i n u t e s a t a t e m p e r a t u r e, 20 ° C$ $o f t h e s u r r o u n d i n g . C a l c u l a t e t h e$ $t e m p e r a t u r e o f t h e b o d y a f t e r$ $a n o t h e r 5 m i n u t e s .$

Question Number 42262 Answers: 1 Comments: 0

Heat is supplied at a rate of 500W to a pressure cooker containing water and fitted with a safety valve.Steam escape such that water is lost at 12g/min.If the heat is supplied at 900W,water is lost at 20g/min.Calculate the specific latent heat of steam.

$H e a t i s s u p p l i e d a t a r a t e o f 500 W$ $t o a p r e s s u r e c o o k e r c o n t a i n i n g$ $w a t e r a n d f i t t e d w i t h a s a f e t y$ $v a l v e . S t e a m e s c a p e s u c h t h a t$ $w a t e r i s l o s t a t 12 g / m i n . I f t h e$ $h e a t i s s u p p l i e d a t 900 W, w a t e r i s$ $l o s t a t 20 g / m i n . C a l c u l a t e t h e$ $s p e c i f i c l a t e n t h e a t o f s t e a m .$

Question Number 42261 Answers: 1 Comments: 1

How much sweat must evaporate from the surface of 150kg of human body to be able to cool the human by 2°C.(assume C=3.35J/g/K for human and L=2.5mJ/kg for water at body temperature)

$H o w m u c h s w e a t m u s t e v a p o r a t e$ $f r o m t h e s u r f a c e o f 150 k g o f h u m a n$ $b o d y t o b e a b l e t o c o o l t h e h u m a n$ $b y 2 ° C . (a s s u m e C = 3.35 J / g / K f o r$ $h u m a n a n d L = 2.5 m J / k g f o r$ $w a t e r a t b o d y t e m p e r a t u r e)$

Question Number 42131 Answers: 1 Comments: 1

Determine the total translational energy of two litres of oxygen gas held at a temperature of 0°C and pressure of one atmosphere.

$D e t e r m i n e t h e t o t a l t r a n s l a t i o n a l$ $e n e r g y o f t w o l i t r e s o f o x y g e n g a s$ $h e l d a t a t e m p e r a t u r e o f 0 ° C a n d$ $p r e s s u r e o f o n e a t m o s p h e r e .$

Question Number 42128 Answers: 0 Comments: 2

Calculate the density of 1 mole of oxygen at a pressure of 4×10^4 Nm^(−2) and temperature of 273.2K.

$C a l c u l a t e t h e d e n s i t y o f 1 m o l e o f$ $o x y g e n a t a p r e s s u r e o f 4 \times 10^{4} {N m}^{- 2}$ $a n d t e m p e r a t u r e o f 273.2 K .$

Question Number 42125 Answers: 0 Comments: 6

If a petrol tank costs σ2000.00 to fill it up at 10°C,how much extra must I pay to fill up the tank at 50°C if the petrol costs σ50.00 per litre and its cubic expansivity is 9.5×10^(−4) K^(−1) ?

$I f a p e t r o l t a n k c o s t s σ 2000.00 t o$ $f i l l i t u p a t 10 ° C, h o w m u c h e x t r a$ $m u s t I p a y t o f i l l u p t h e t a n k a t 50 ° C$ $i f t h e p e t r o l c o s t s σ 50.00 p e r l i t r e$ $a n d i t s c u b i c e x p a n s i v i t y i s$ $9.5 \times 10^{- 4} K^{- 1} ?$

Question Number 41888 Answers: 0 Comments: 5

The length of mercury column in a mercury-in-glass thermometer is 4cm at triple point.What is the length of the column when the scale indicates temperature of 560K.

$T h e l e n g t h o f m e r c u r y c o l u m n i n$ $a m e r c u r y - i n - g l a s s t h e r m o m e t e r$ $i s 4 c m a t t r i p l e p o i n t . W h a t i s t h e$ $l e n g t h o f t h e c o l u m n w h e n t h e$ $s c a l e i n d i c a t e s t e m p e r a t u r e o f$ $560 K .$

Question Number 40498 Answers: 1 Comments: 0

A gas at 17° has the ratio of its initial to final volume as 25 with initial pressure of 2×10^5 Nm^(−2) .Calculate the final pressure and temperature after compression.(γ=1.5)

$A g a s a t 17 ° h a s t h e r a t i o o f i t s i n i t i a l$ $t o f i n a l v o l u m e a s 25 w i t h i n i t i a l$ $p r e s s u r e o f 2 \times 10^{5} {N m}^{- 2} . C a l c u l a t e$ $t h e f i n a l p r e s s u r e a n d t e m p e r a t u r e$ $a f t e r c o m p r e s s i o n . (γ = 1.5)$

Question Number 39237 Answers: 0 Comments: 1

Calculate the triple point for an electrical resistance thermometer, assuming the ratio of resistance at the triple point to that at initial point is 2.0.

$C a l c u l a t e t h e t r i p l e p o i n t f o r a n$ $e l e c t r i c a l r e s i s t a n c e t h e r m o m e t e r,$ $a s s u m i n g t h e r a t i o o f r e s i s t a n c e$ $a t t h e t r i p l e p o i n t t o t h a t a t i n i t i a l$ $p o i n t i s 2.0 .$

Question Number 39236 Answers: 0 Comments: 3

If a petrol tank costs $2000.00 to fill it up at 10°C ,how much extra dollar must I pay to fill up the tank at 50°C,if the petrol costs $50.00 per litre and its cubic expansivity is 9.5×10^(−4) K^(−1) ?

$I f a p e t r o l t a n k c o s t s $ 2000.00 t o$ $f i l l i t u p a t 10 ° C, h o w m u c h e x t r a$ $d o l l a r m u s t I p a y t o f i l l u p t h e t a n k$ $a t 50 ° C, i f t h e p e t r o l c o s t s $ 50.00$ $p e r l i t r e a n d i t s c u b i c e x p a n s i v i t y$ $i s 9.5 \times 10^{- 4} K^{- 1} ?$

Question Number 39235 Answers: 0 Comments: 1

The length of a mercury column in a mercury in glass thermometer is 4cm at triple point.What is the length of the column when the scale indicates temperature of 560K.

$T h e l e n g t h o f a m e r c u r y c o l u m n$ $i n a m e r c u r y i n g l a s s t h e r m o m e t e r$ $i s 4 c m a t t r i p l e p o i n t . W h a t i s t h e$ $l e n g t h o f t h e c o l u m n w h e n t h e$ $s c a l e i n d i c a t e s t e m p e r a t u r e o f 560 K .$

Question Number 34892 Answers: 0 Comments: 0

Question Number 34891 Answers: 1 Comments: 0

Question Number 32264 Answers: 0 Comments: 1

Question Number 31474 Answers: 1 Comments: 1

A vacuum chamber has a door with surface dimensions 20cm×20cm.How many 70kg men, each exerting a pull equal to his weight,will it take to pull the door open when the chamber is evacuated to a pressure of 0.1 atm?

$A v a c u u m c h a m b e r h a s a d o o r$ $w i t h s u r f a c e d i m e n s i o n s$ $20 c m \times 20 c m . H o w m a n y 70 k g m e n,$ $e a c h e x e r t i n g a p u l l e q u a l t o h i s$ $w e i g h t, w i l l i t t a k e t o p u l l t h e$ $d o o r o p e n w h e n t h e c h a m b e r i s$ $e v a c u a t e d t o a p r e s s u r e o f 0.1 a t m ?$

Question Number 31326 Answers: 1 Comments: 1

Question Number 31209 Answers: 1 Comments: 2

Question Number 31114 Answers: 1 Comments: 2

Question Number 27447 Answers: 1 Comments: 0

∫^∞ _0 v^(4 ) e ((−mv^2 )/(2KT))dv solve it

${\int_{0}}^{\infty} v^{4} e \frac{- {mv}^{2}}{2 KT} dv$ $solve it$

Pg 1 Pg 2 Pg 3

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