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Question Number 70361 by mind is power last updated on 03/Oct/19

$$Hello$$$$si\left(x\right)=-{\int }_x^{\mathrm{\infty }}\frac{sin\left(x\right)}{x}dx$$$$show{\int }_0^{+\mathrm{\infty }}{x}^{a-1}si\left(x\right)dx=-\frac{\mathrm{\Gamma }\left(a\right)sin\left(\frac{\pi a}{2}\right)}{a}$$$$hintipp+complexAnalysis$$

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