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Question Number 67659 by Rio Michael last updated on 29/Aug/19
Helpmeobtainthevalueofefrom(1+1n)nhowdoigoaboutit.
Commented by Abdo msup. last updated on 30/Aug/19
An=(1+1n)nandlimn→+∞An=eAn=∑k=0nCnk1nk=Cn0n0+Cn1n1+Cn2n2+Cn3n3+..+Cnnnn⇒e=limn→+∞An=1+1+Cn2n2+Cn3n3+....=2+n(n−1)2n2+n(n−1)(n−2)6n3+...wdfinde∼2,7...
Commented by Rio Michael last updated on 30/Aug/19
thankssir
youarewelcome.
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