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Question Number 11754 by Joel576 last updated on 31/Mar/17
Howmanynumbersbetween1−2017thataren′tdivisibleby5,6,7,8?
Answered by mrW1 last updated on 31/Mar/17
leta=countofnumberswhicharemultipleof5letb=countofnumberswhicharemultipleof6letc=countofnumberswhicharemultipleof7letd=countofnumberswhicharemultipleof8a=2017/5=403a1=2017/(5×6)=67(alsoinb)a2=2017/(5×7)=57(alsoinc)a3=2017/(5×8)=50(alsoind)b=2017/6=336b1=2017/(6×7)=48(alsoinc)b2=2017/(6×8)=42(alsoind)c=2017/7=288c1=2017/(7×8)=36(alsoind)d=2017/8=252a1,a2,a3,b1,b2,c1arecountofnumberswhicharedoublecounted.countofnumberswhicharedivisibleby5,6,7,8:a+b+c+d−a1−a2−a3−b1−b2−c1=403+336+288+252−67−57−50−48−42−36=979countofnumberswhicharenotdivisibleby5,6,7,8:2017−979=1038
Commented by Joel576 last updated on 01/Apr/17
thankyouverymuch
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