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Question Number 124372 by mr W last updated on 02/Dec/20

$$Howmanysix-digitnumberscontain$$$$exactlysixdifferentdigits?$$

Answered by bemath last updated on 02/Dec/20

$$=9\times P_5^9=9\times \frac{9!}{4!}$$$$=9\times 9\times 8\times 7\times 6\times 5=136080$$

Commented by mr W last updated on 03/Dec/20

$$thanks!$$

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