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Question Number 134329 by bramlexs22 last updated on 02/Mar/21

$$$$How many ways can 15 basketball players be assigned to Team A, Team B, and Team C with 5 players on each team?

Answered by EDWIN88 last updated on 02/Mar/21

$$=\frac{15!}{{(5!)}^3}=756756$$

Answered by mr W last updated on 02/Mar/21

$$C_5^{15}\times C_5^{10}=756756$$

Commented by otchereabdullai@gmail.com last updated on 12/Mar/21

$$\mathrm{wow}!$$

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