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Question Number 209624 by mnjuly1970 last updated on 16/Jul/24
I=∫0∞∫0∞11+x2+y2+x2y2dxdy=?usingpolarsystem...
Answered by mr W last updated on 16/Jul/24
=∫0∞∫0∞1(1+x2)(1+y2)dxdy=[∫0∞11+x2dx]2=([tan−1x]0∞)2=(π2)2=π24
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