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Question Number 66276 by gunawan last updated on 12/Aug/19
Ifaandbisrootequation3log3(4x2+3)+4log2(x2−1)=49thena+b=..a.3b.2c.1d.0e.−1
Answered by Kunal12588 last updated on 12/Aug/19
3log3(4x2+3)+4log2(x2−1)=49⇒4x2+3+(x2−1)2=49⇒x4−2x2+1+4x2+3−49=0⇒x4+2x2−45=0⇒x2=−2±4+1802=−2±2462=−1±46⇒x=±46−1⇒a=46−1,b=−46−1⇒a+b=0
Commented by gunawan last updated on 12/Aug/19
thanksSir
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