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Question Number 178818 by Shrinava last updated on 21/Oct/22
Ifa,b,c,d∈[1,2]thenprovethat:(a+b+c+d+e)(1a+1b+1c+1d+1e)⩽28Whenequalityholds?
Answered by mr W last updated on 22/Oct/22
A=a+b+c+d+eB=1a+1b+1c+1d+1eΦ=A×Bwesee,whenwemakeAlarger,wemakeBsmallerinthesametime.tomakeAlarger,weshouldmakeasmanynumbersaspossibleequalto2.buttomakeBlarger,weshouldmakeasmanynumbersaspossibleequalto1.wehave5numbers.let′ssaynnumbersequal2and5−nnumbersequal1.A=n×2+(5−n)×1=n+5B=n×12+(5−n)×11=5−n2Φ=(n+5)(5−n2)=50+5n−n22=2258−12(n−52)2sincenisinteger,n≠52.Φmaxisatn=2or3.Φmax=2258−12×(12)2=2248=28i.e.Φ⩽28.theequalityholdswhen2numbersequalto2and3numbersequalto1,orwhen3numbersequalto2and2umbersequalto1.
Commented by Tawa11 last updated on 22/Oct/22
Greatsir
Commented by Shrinava last updated on 23/Oct/22
cooldearprofessorthankyousomuch
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