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Question Number 178818 by Shrinava last updated on 21/Oct/22

If   a,b,c,d∈[1,2]   then prove that:  (a + b + c + d + e)((1/a) + (1/b) + (1/c) + (1/d) + (1/e)) ≤ 28  When equality holds?

Ifa,b,c,d[1,2]thenprovethat:(a+b+c+d+e)(1a+1b+1c+1d+1e)28Whenequalityholds?

Answered by mr W last updated on 22/Oct/22

A=a+b+c+d+e  B=(1/a)+(1/b)+(1/c)+(1/d)+(1/e)  Φ=A×B  we see, when we make A larger, we  make B smaller in the same time.  to make A larger, we should make  as many numbers as possible equal  to 2. but to make B larger, we should  make as many numbers as possible   equal to 1.  we have 5 numbers. let′s say n numbers  equal 2 and 5−n numbers equal 1.  A=n×2+(5−n)×1=n+5  B=n×(1/2)+(5−n)×(1/1)=5−(n/2)  Φ=(n+5)(5−(n/2))=((50+5n−n^2 )/2)     =((225)/8)−(1/2)(n−(5/2))^2   since n is integer, n≠(5/2).  Φ_(max)  is at n=2 or 3.  Φ_(max) =((225)/8)−(1/2)×((1/2))^2 =((224)/8)=28  i.e. Φ≤28. the equality holds when  2 numbers equal to 2 and 3 numbers  equal to 1, or when 3 numbers equal  to 2 and 2 umbers equal to 1.

A=a+b+c+d+eB=1a+1b+1c+1d+1eΦ=A×Bwesee,whenwemakeAlarger,wemakeBsmallerinthesametime.tomakeAlarger,weshouldmakeasmanynumbersaspossibleequalto2.buttomakeBlarger,weshouldmakeasmanynumbersaspossibleequalto1.wehave5numbers.letssaynnumbersequal2and5nnumbersequal1.A=n×2+(5n)×1=n+5B=n×12+(5n)×11=5n2Φ=(n+5)(5n2)=50+5nn22=225812(n52)2sincenisinteger,n52.Φmaxisatn=2or3.Φmax=225812×(12)2=2248=28i.e.Φ28.theequalityholdswhen2numbersequalto2and3numbersequalto1,orwhen3numbersequalto2and2umbersequalto1.

Commented by Tawa11 last updated on 22/Oct/22

Great sir

Greatsir

Commented by Shrinava last updated on 23/Oct/22

cool dear professor thank you so much

cooldearprofessorthankyousomuch

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