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Question Number 182947 by myint last updated on 17/Dec/22
Ifa<b<0,then∣a−b∣+∣a+b∣+∣ab∣=
Commented by mr W last updated on 17/Dec/22
≠constantvalue!couldbeanypositivevalue!
Answered by Frix last updated on 17/Dec/22
a<b<0⇒a−b<0∧a+b<0∧ab>0⇒∣a−b∣+∣a+b∣+∣ab∣==−(a−b)−(a+b)+ab==−2a+ab=a(b−2)
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