If a regular n−polygon can be divided into n identical equilateral triangles then n=6


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Question Number 196320 by sniper237 last updated on 22/Aug/23

$I f a r e g u l a r n - p o l y g o n c a n$ $b e d i v i d e d i n t o n i d e n t i c a l$ $e q u i l a t e r a l t r i a n g l e s t h e n n = 6$
	Answered by Rasheed.Sindhi last updated on 23/Aug/23

	$n - p o l y g o n c o n s i s t s n e q u i l a t e r a l t r i a n g l e s$ $∴ C e n t r a l a n g l e = 60$ $C e n t r a l a n g l e = \frac{360}{n} = 60 \Rightarrow n = 6$
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