Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 110157 by I want to learn more last updated on 27/Aug/20

$$\mathrm{If}\mathrm{we}\mathrm{have}5\mathrm{people},\mathrm{how}\mathrm{many}\mathrm{ways}\mathrm{can}\mathrm{they}\mathrm{be}\mathrm{seated}$$$$\mathrm{on}\mathrm{a}\mathrm{round}\mathrm{table},\mathrm{if}\mathrm{there}\mathrm{are},$$$$\left(\mathrm{a}\right)7\mathrm{chairs}\left(\mathrm{b}\right)3\mathrm{chairs}\mathrm{available}$$

Answered by bemath last updated on 27/Aug/20

$$\left(a\right)C_5^7\times 4!=\frac{7\times 6}{2\times 1}\times 24=21\times 24way$$

Answered by I want to learn more last updated on 27/Aug/20

$$\mathrm{Thanks}\mathrm{sir}.$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com