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Question Number 188072 by Shrinava last updated on 25/Feb/23

$$\mathrm{If}{\mathrm{x}}_1=-1\mathrm{and}{\mathrm{x}}_{\mathbf{n}+1}=(1+\frac{2}{\mathrm{n}}){\mathrm{x}}_{\mathbf{n}}+\frac{4}{\mathrm{n}}$$$$\mathrm{Find}{\mathrm{x}}_{2023}=?$$

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