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Question Number 112803 by Aina Samuel Temidayo last updated on 09/Sep/20

$$\mathrm{If}\mathrm{x}+\mathrm{y}+\mathrm{z}=0,$$$$\mathrm{then}\mathrm{the}\mathrm{value}\mathrm{of}\frac{{\mathrm{x}}^2+{\mathrm{y}}^2+{\mathrm{z}}^2}{{\mathrm{x}}^2-\mathrm{yz}}\mathrm{is}$$

Answered by MJS_new last updated on 09/Sep/20

$$z=-(x+y)\Rightarrow \frac{x^2+y^2+z^2}{x^2-yz}=2$$

Commented by Aina Samuel Temidayo last updated on 09/Sep/20

$$\mathrm{Solution}?$$

Commented by MJS_new last updated on 09/Sep/20

$$\mathrm{just}\mathrm{insert}\mathrm{and}\mathrm{calculate}$$

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