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Question Number 19730 by Tinkutara last updated on 15/Aug/17

$$\mathrm{If}z=x+iy\mathrm{and}\mid z-2i\mid =1,\mathrm{then}$$$$\left(1\right)z\mathrm{lies}\mathrm{on}x-\mathrm{axis}$$$$\left(2\right)z\mathrm{lies}\mathrm{on}y-\mathrm{axis}$$$$\left(3\right)z\mathrm{lies}\mathrm{on}\mathrm{a}\mathrm{circle}$$$$\left(4\right)\mathrm{None}\mathrm{of}\mathrm{these}$$

Answered by ajfour last updated on 15/Aug/17

$$\mathrm{z}\mathrm{lies}\mathrm{on}\mathrm{s}\mathrm{circle}\mathrm{with}\mathrm{centre}\mathrm{at}$$$${\mathrm{z}}_0=2\mathrm{i}\mathrm{and}\mathrm{radius}=1.$$

Commented by Tinkutara last updated on 15/Aug/17

$$\mathrm{Thank}\mathrm{you}\mathrm{very}\mathrm{much}\mathrm{Sir}!$$

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