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Question Number 66066 by Kunal12588 last updated on 08/Aug/19
Integrate∫dxax2+bx+cy=ax2+bx+cy′=dydx=2ax+bd=b2−4acd′=−dCase1.d2<0I=2d′tan−1y′d′+C[tan−1α=arctanα]Case2.d2=0I=−2y′+CCase3.d2>0I=1dln∣y′−dy′+d∣+C[lna=logea]
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