Question and Answers Forum

All Questions Topic List

IntegrationQuestion and Answers: Page 187

Question Number 85391 Answers: 1 Comments: 5

Question Number 85384 Answers: 1 Comments: 1

Question Number 85383 Answers: 1 Comments: 0

∫(((sin(x))/(cos^(11) (x))))^(1/5) dx

$\int \sqrt[5]{\frac{s i n (x)}{{c o s}^{11} (x)}} d x$

Question Number 85362 Answers: 1 Comments: 0

∫((−4−u)/(u^2 +5u+6))du

$\int \frac{- 4 - u}{u^{2} + 5 u + 6} du$

Question Number 85360 Answers: 1 Comments: 0

∫(e^((1−x)×e^x ) ×e^(∫xe^x dx) )dx

$\int (e^{(1 - x) \times e^{x}} \times e^{\int {xe}^{x} dx}) dx$

Question Number 85355 Answers: 1 Comments: 4

Question Number 85374 Answers: 0 Comments: 2

∫_0 ^1 ((x^7 +x^3 +1)/(x^4 +1)) dx

$\int_{0}^{1} \frac{x^{7} + x^{3} + 1}{x^{4} + 1} d x$

Question Number 85323 Answers: 1 Comments: 0

∫((z−3)/(5z−10))dz

$\int \frac{z - 3}{5 z - 10} dz$

Question Number 85321 Answers: 0 Comments: 0

Question Number 85319 Answers: 1 Comments: 0

∫((2+u)/(−u^2 −u))du

$\int \frac{2 + u}{- u^{2} - u} du$

Question Number 85260 Answers: 1 Comments: 1

Evaluate using cauchy′s integral ∫_c (e^(iπ) /((z^2 +4)^2 (z+1)^2 ))dz where c is a circle with ∣z−i∣=3.5 help please

$Evaluate using {cauchy}^{'} s integral$ $\int_{c} \frac{e^{i π}}{{(z^{2} + 4)}^{2} {(z + 1)}^{2}} dz$ $where c is a circle with ∣ z - i ∣= 3.5$ $help please$

Question Number 85256 Answers: 0 Comments: 3

∫ _0 ^( 1) ((sin (ln x))/(ln (x))) dx

$\int \underset{0}{\overset{1}{}} \frac{\sin (\ln x)}{\ln (x)} dx$

Question Number 85254 Answers: 0 Comments: 0

Question Number 85236 Answers: 1 Comments: 1

find f(x) if f ′(x) + f(x^2 ) = 2x+1

$find f (x) if$ $f^{'} (x) + f (x^{2}) = 2 x + 1$

Question Number 85191 Answers: 2 Comments: 0

∫((z+2)/z)

$\int \frac{z + 2}{z}$

Question Number 85167 Answers: 0 Comments: 0

let ϕ(x)=Γ(x).Γ(1−x) find ∫_(1/3) ^(1/2) ln(ϕ(x))dx

$l e t φ (x) = Γ (x) . Γ (1 - x) f i n d \int_{\frac{1}{3}}^{\frac{1}{2}} l n (φ (x)) d x$

Question Number 85166 Answers: 1 Comments: 3

find ∫ (x^2 −1)(√(x^2 +1))dx

$f i n d \int (x^{2} - 1) \sqrt{x^{2} + 1} d x$

Question Number 85162 Answers: 0 Comments: 1

1)find ∫ ln((√x)+(√(x+1)))dx 2) calculate ∫_0 ^1 ln((√x)+(√(x+1)))dx

$1) f i n d \int l n (\sqrt{x} + \sqrt{x + 1}) d x$ $2) c a l c u l a t e \int_{0}^{1} l n (\sqrt{x} + \sqrt{x + 1}) d x$

Question Number 85160 Answers: 1 Comments: 2

1) find f(a) =∫_0 ^∞ (dx/(x^4 +a)) with a>0 2) find g(a)=∫_0 ^∞ (dx/((x^4 +a)^2 )) 3) find value of integrals ∫_0 ^∞ (dx/(x^4 +1)) ,∫_0 ^∞ (dx/(2x^4 +8)) ∫_0 ^∞ (dx/((x^4 +1)^2 )) and ∫_0 ^∞ (dx/((2x^4 +8)^2 ))

$1) f i n d f (a) = \int_{0}^{\infty} \frac{d x}{x^{4} + a} w i t h a > 0$ $2) f i n d g (a) = \int_{0}^{\infty} \frac{d x}{{(x^{4} + a)}^{2}}$ $3) f i n d v a l u e o f i n t e g r a l s \int_{0}^{\infty} \frac{d x}{x^{4} + 1}, \int_{0}^{\infty} \frac{d x}{2 x^{4} + 8}$ $\int_{0}^{\infty} \frac{d x}{{(x^{4} + 1)}^{2}} a n d \int_{0}^{\infty} \frac{d x}{{(2 x^{4} + 8)}^{2}}$

Question Number 85158 Answers: 0 Comments: 0

calculate U_n = ∫_(−(1/n)) ^(1/n) x^2 (√((1−x)/(1+x)))dx (n integr and n≥2) 2) find nature of Σ U_n

$c a l c u l a t e U_{n} = \int_{- \frac{1}{n}}^{\frac{1}{n}} x^{2} \sqrt{\frac{1 - x}{1 + x}} d x (n i n t e g r a n d n ⩾ 2)$ $2) f i n d n a t u r e o f Σ U_{n}$

Question Number 85148 Answers: 0 Comments: 0

∫_0 ^1 ((1+x^4 )/(1+x^3 +x^7 )) dx

$\int_{0}^{1} \frac{1 + x^{4}}{1 + x^{3} + x^{7}} d x$

Question Number 85097 Answers: 1 Comments: 0

∫_(−π) ^π x^(2020) (sin x+cos x) dx = 8 find ∫_(−π) ^π x^(2020) cos x dx = ?

$\underset{- π}{\int^{π}} x^{2020} (\sin x + \cos x) dx = 8$ $find \underset{- π}{\int^{π}} x^{2020} \cos x dx = ?$

Question Number 85059 Answers: 1 Comments: 0

Question Number 85009 Answers: 1 Comments: 1

calculate ∫_0 ^∞ (x^n /(sh(x)))dx with n integr natural

$c a l c u l a t e \int_{0}^{\infty} \frac{x^{n}}{s h (x)} d x w i t h n i n t e g r n a t u r a l$

Question Number 84958 Answers: 0 Comments: 0

Question Number 84957 Answers: 0 Comments: 1

∫ (2−x^2 )^3 dx =

$\int {(2 - x^{2})}^{3} dx =$

Pg 182 Pg 183 Pg 184 Pg 185 Pg 186 Pg 187 Pg 188 Pg 189 Pg 190 Pg 191

Contact: info@tinkutara.com