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All Questions Topic List |
IntegrationQuestion and Answers: Page 3 |
Question Number 218583 Answers: 1 Comments: 0
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∫_(0 ) ^∞ e^(−x) (Σ_(n=1) ^∞ ((f(n))/n) sin(nx))dx =1
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Question Number 218582 Answers: 1 Comments: 0
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∫_0 ^∞ ((cos(ax) − cos(bx))/x^2 ) dx = (π/2) ∣b−a∣
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Question Number 218563 Answers: 0 Comments: 0
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solve for x ∈ R
∫_0 ^∞ ((sin(xt))/(e^t −1 )) dt = (𝛑/2) coth(𝛑x) − (1/(2x))
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Question Number 218560 Answers: 0 Comments: 1
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Question Number 218462 Answers: 2 Comments: 0
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∫(dx/( (√(2x−x^2 +3))))
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Question Number 218398 Answers: 1 Comments: 0
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Question Number 218395 Answers: 0 Comments: 0
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Question Number 218383 Answers: 0 Comments: 2
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Question Number 218376 Answers: 0 Comments: 0
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∫_0 ^∞ ((J_𝛂 (ar))/((r^2 +k^2 )𝛍))dr
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Question Number 218375 Answers: 1 Comments: 0
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∫((√(tan x))/(sin^3 x cos x))dx
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Question Number 218374 Answers: 0 Comments: 0
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∫_0 ^∞ J_α ((√(ar)))e^(−r) dr
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Question Number 218322 Answers: 1 Comments: 0
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Evaluate ∫_0 ^(π/2) ((sin(x))/(sin^3 (x)+cos^3 (x))) dx.
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Question Number 218150 Answers: 1 Comments: 0
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∫_0 ^1 (1/(1−x^2 ))ln(((1+x)/(2x)))dx
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Question Number 218148 Answers: 2 Comments: 0
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I=∫_0 ^( ∞) ((sin((√( x ))))/( (( e^x ))^(1/4) ))dx=?
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Question Number 218054 Answers: 0 Comments: 0
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Question Number 217881 Answers: 2 Comments: 0
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Question Number 217813 Answers: 1 Comments: 0
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∫_0 ^∞ [(xp(2+x)]^(−1) dx
p∈R
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Question Number 217804 Answers: 0 Comments: 0
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Question Number 217755 Answers: 2 Comments: 2
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∫ ((cos(sin^(− 1) x) + cos^(− 1) (sin x))/(ln(ln(ln(1 + (√(x + (√x)))))) dx
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Question Number 217761 Answers: 1 Comments: 0
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prove that :
I=∫_0 ^( ∞) ((sin(πx)sin(2πx)sin(3πx))/x^3 ) = π^3
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Question Number 217683 Answers: 0 Comments: 0
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Prove:∫_0 ^1 (√((((√(K^2 +36K′^2 ))+6K^′ )/(K^2 +36K^(′2) )) ))(dk/( (√k)(1−k^2 )^(2/3) ))=(√π)((√2)−(√((4−2(√2))/3)))
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Question Number 217685 Answers: 0 Comments: 0
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Question Number 217626 Answers: 1 Comments: 0
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lim_( λ→0) ∫_λ ^( 2λ) (( e^(2t ) )/t) dt = ?
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Question Number 217441 Answers: 2 Comments: 0
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∫_0 ^1 ((ln^3 (1−x))/x^3 ) dx=?
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Question Number 217431 Answers: 2 Comments: 0
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Question Number 217423 Answers: 1 Comments: 0
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