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IntegrationQuestion and Answers: Page 322

Question Number 21721    Answers: 1   Comments: 0

∫_0 ^(π/2) sin^2 xcos^3 xdx

0π/2sin2xcos3xdx

Question Number 21720    Answers: 1   Comments: 0

∫sin^5 θdθ

sin5θdθ

Question Number 21707    Answers: 0   Comments: 3

∫_(π/6) ^(π/3) (1/2)cot^2 2θdθ

π/6π/312cot22θdθ

Question Number 21702    Answers: 0   Comments: 1

∫_(π/6) ^(π/3) 1/2cot^2 2θdθ

π/6π/31/2cot22θdθ

Question Number 21701    Answers: 2   Comments: 1

∫2cot^2 2t

2cot22t

Question Number 21662    Answers: 1   Comments: 0

Question Number 21679    Answers: 1   Comments: 0

∫((secθ dθ)/(1−secθ))

secθdθ1secθ

Question Number 21680    Answers: 1   Comments: 0

∫(√(secθ)) dθ

secθdθ

Question Number 21634    Answers: 1   Comments: 0

∫3tan2t

3tan2t

Question Number 21708    Answers: 1   Comments: 0

∫_0 ^(0.5) 2tan^2 2tdt

00.52tan22tdt

Question Number 21591    Answers: 1   Comments: 1

5cos^5 tsin t

5cos5tsint

Question Number 21595    Answers: 1   Comments: 1

3sec^2 3xtan3x

3sec23xtan3x

Question Number 21582    Answers: 1   Comments: 0

∫_(π/2) ^(π/4) (3x+7)

π/2π/4(3x+7)

Question Number 21450    Answers: 0   Comments: 0

Question Number 21390    Answers: 0   Comments: 0

∫_0 ^1 ((x^7 − 1)/(ln x)) dx

10x71lnxdx

Question Number 21212    Answers: 0   Comments: 0

Question Number 21205    Answers: 0   Comments: 1

Question Number 21077    Answers: 1   Comments: 0

integrate with respect to x ∫(dx/(9x^2 +6x+10))

integratewithrespecttoxdx9x2+6x+10

Question Number 21076    Answers: 1   Comments: 0

integrate with respect to x ∫x^(sinx)

integratewithrespecttoxxsinx

Question Number 20939    Answers: 0   Comments: 0

Demostration of the volume of an sphere V=((4πr^3 )/3) x^2 +y^2 +z^2 =r^2 We divide the sphere in 8 parts. So the volume of a part is ∫_0 ^( r) ∫_0 ^( (√(r^2 −x^2 ))) (√(r^2 −x^2 −y^2 ))∂y∂x Lets asumme a^2 =r^2 −x^2 ∫_0 ^( r) ∫_0 ^( a) (√(a^2 −y^2 ))∂y∂x ∫_0 ^( r) a∫_0 ^( a) (√(1−((y/a))^2 ))∂y∂x Lets assume (y/a)=sinθ⇒(∂y/a)=cosθ∂θ ∫(√(1−sin^2 θ))acosθ∂θ ∫acos^2 θ∂θ a((θ/2)−((sin2θ)/4)) a(((arcsin((y/a)))/2)−((y(√(a^2 −y^2 )))/(2a^2 ))) ∫_0 ^( r) a^2 (((arcsin((y/a)))/2)−((y(√(a^2 −y^2 )))/(2a^2 )))∣_0 ^a ∂x ∫_0 ^( r) (((a^2 arcsin((y/a))−y(√(a^2 −y^2 )))/2))∣_0 ^a ∂x ∫_0 ^( r) ((πa^2 )/4)∂x ∫_0 ^( r) ((π(r^2 −x^2 ))/4)∂x (((6πr^2 x−2πx^3 )/(24)))∣_0 ^r ((πr^3 )/6)=1/8Volume of the sphrere so... V=((4πr^3 )/3)

DemostrationofthevolumeofansphereV=4πr33x2+y2+z2=r2Wedividethespherein8parts.Sothevolumeofapartis0r0r2x2r2x2y2yxLetsasummea2=r2x20r0aa2y2yx0ra0a1(ya)2yxLetsassumeya=sinθya=cosθθ1sin2θacosθθacos2θθa(θ2sin2θ4)a(arcsin(ya)2ya2y22a2)0ra2(arcsin(ya)2ya2y22a2)0ax0r(a2arcsin(ya)ya2y22)0ax0rπa24x0rπ(r2x2)4x(6πr2x2πx324)0rπr36=1/8Volumeofthesphrereso...V=4πr33

Question Number 20908    Answers: 1   Comments: 0

integrate with respect to x ∫(((2x+1)/(x^2 +4x+8)))dx

integratewithrespecttox(2x+1x2+4x+8)dx

Question Number 20905    Answers: 1   Comments: 1

∫e^x^2 dx

ex2dx

Question Number 20873    Answers: 1   Comments: 0

∫_1 ^5 (e^x /x^2 ) dx

15exx2dx

Question Number 20857    Answers: 0   Comments: 0

∫ (√(sin x)) + (√(cos x)) dx

sinx+cosxdx

Question Number 20733    Answers: 1   Comments: 0

Find the volume of the solid of revolution obtained by revolving area bounded by x = 4 + 6y − 2y^2 , x = −4, x = 0 about the y−axis

Findthevolumeofthesolidofrevolutionobtainedbyrevolvingareaboundedbyx=4+6y2y2,x=4,x=0abouttheyaxis

Question Number 20686    Answers: 2   Comments: 1

∫(tanx)^(1/3) dx

(tanx)1/3dx

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