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All Questions Topic List |
IntegrationQuestion and Answers: Page 34 |
Question Number 179175 Answers: 0 Comments: 2
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Find ∫x^5 (√(x^3 +1)) dx
Answer: I= (2/(45)) (3x^3 −2) (√((x^3 +1)^3 )) + c
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Question Number 179181 Answers: 3 Comments: 0
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Help-me!
Use double integral to find the area of the
region bounded by the following curves
given in the plane shown below:
y^2 = 4x and x^2 = 4y
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Question Number 179107 Answers: 1 Comments: 0
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I= ∫ (x^2 /(sin (2arctan (e^x )))) dx , Find I
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Question Number 179066 Answers: 1 Comments: 0
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If f(x)=∫ (x^2 /(x^2 +tan x)) dx
then ∫ ((tan x)/(x^2 +tan x)) dx =?
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Question Number 179042 Answers: 2 Comments: 0
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Question Number 178988 Answers: 1 Comments: 0
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C = ∫_0 ^(π/2) ((cos^2 x)/(4sin^2 x+cos^2 x)) dx =?
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Question Number 178922 Answers: 1 Comments: 0
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Question Number 178879 Answers: 0 Comments: 0
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Question Number 178832 Answers: 4 Comments: 0
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Question Number 178712 Answers: 1 Comments: 0
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Question Number 178693 Answers: 1 Comments: 6
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Prove that
∫_0 ^(π/2) ((tan 2x)/( (√(sin^4 x+4cos^2 x)) −(√(cos^4 x+4sin^2 x))))=1
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Question Number 178692 Answers: 1 Comments: 0
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∫((tan (ln x).tan (ln (x/2)).tan (ln 2))/x)dx
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Question Number 178657 Answers: 0 Comments: 0
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calculate
I=∫_0 ^( (π/4)) (( sin(x))/(1+ tan(2x))) dx = ?
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Question Number 178563 Answers: 2 Comments: 0
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∫e^x^2 dx=?
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Question Number 178550 Answers: 1 Comments: 0
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Question Number 179991 Answers: 1 Comments: 0
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Question Number 178341 Answers: 1 Comments: 0
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Question Number 178246 Answers: 1 Comments: 0
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Question Number 177913 Answers: 0 Comments: 0
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if I_n =∫xsin^n x dx and
I_n = −((xsin^(n−1) x cosx )/n) +((sin^n x )/n^2 )+f(n)I_(n−2)
then f(n) = ?
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Question Number 177906 Answers: 1 Comments: 0
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∫_0 ^1 ((sin x(cos^2 x−cos^2 (π/5))(cos^2 x−cos^2 ((2π)/5)))/(sin 5x)) dx =?
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Question Number 177820 Answers: 2 Comments: 0
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∫_(π/2) ^π (dx/((sin x−2cos x)^2 )) =?
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Question Number 177784 Answers: 1 Comments: 0
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Question Number 177775 Answers: 1 Comments: 0
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∫((sin2x)/( (√(cos^4 x+1))))dx
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Question Number 177604 Answers: 0 Comments: 0
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Calculate
𝛗=∫_0 ^( 1) (( ln(x ))/(1 + x^( 2) )) dx =^? −G
∼ Solution ∼
𝛗 = ∫_0 ^( 1) {Σ_(k=0) ^∞ (−1)^( k) x^( 2k) ln(x) }dx
= Σ_(k=0) ^∞ (−1 )^( k) ∫_0 ^( 1) x^( 2k) ln(x) dx
=^(i.b.p) Σ_(k=0) ^∞ (−1 )^( k) {[(x^( 1+2k) /(1+2k)) ln(x ) ]_0 ^1 −(1/(1+2k))∫_0 ^( 1) x^( 2k) dx }
= Σ_(k=0) ^∞ (( (−1)^(1+k) )/(( 1 + 2k )^( 2) )) = − G ( Catalan constant )
∴ 𝛗 = − G ■ m.n
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Question Number 177541 Answers: 0 Comments: 3
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Question Number 178487 Answers: 3 Comments: 0
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∫ (dx/(cot^3 x sin^7 x)) =?
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Pg 29
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