Question and Answers Forum

IntegrationQuestion and Answers: Page 9

Question Number 210082 Answers: 1 Comments: 0

prove that ∫_0 ^1 ((ln(1−t+tx^2 ))/(x^2 −1))dx=(sin^(−1) ((√t)))^2 please anyone..

$prove that$ $\int_{0}^{1} \frac{\ln (1 - t + {tx}^{2})}{x^{2} - 1} dx = {(\sin^{- 1} (\sqrt{t}))}^{2}$ $please anyone . .$

Question Number 210032 Answers: 3 Comments: 0

∫_6 ^0 (2+5x)e^((1/3)x) dx

$\int_{6}^{0} (2 + 5 x) e^{\frac{1}{3} x} dx$

Question Number 209923 Answers: 1 Comments: 0

Solve: ∫((sin(x!))/(x!))dx

$S o l v e : \int \frac{s i n (x!)}{x!} d x$

Question Number 209800 Answers: 1 Comments: 1

Question Number 209773 Answers: 0 Comments: 0

Question Number 209691 Answers: 0 Comments: 0

∫(2x^(3x^2 +4x−7) )(log _2 (x^2 +3x−7))e^(x^2 +3x−5) dx=?

$\int ({2 x}^{{3 x}^{2} + 4 x - 7}) (\log_{2} (x^{2} + 3 x - 7)) e^{x^{2} + 3 x - 5} dx = ?$

Question Number 209687 Answers: 3 Comments: 0

Question Number 209685 Answers: 1 Comments: 0

Question Number 209662 Answers: 1 Comments: 0

∫(1/(sin^2 x(1+cos^2 x)))dx

$\int \frac{1}{\sin^{2} x (1 + \cos^{2} x)} d x$

Question Number 209557 Answers: 2 Comments: 0

Given ∫_2 ^4 (ax^n +1)dx=58 ∫_0 ^2 (ax^n +1)dx=10 find the value of a and n

$G i v e n$ $\int_{2}^{4} ({a x}^{n} + 1) d x = 58 \int_{0}^{2} ({a x}^{n} + 1) d x = 10$ $f i n d t h e v a l u e o f a a n d n$

Question Number 209544 Answers: 1 Comments: 0

∫_0 ^4 (dx/(∣x−1∣+∣x−2∣+∣x−4∣))

$\int_{0}^{4} \frac{d x}{∣ x - 1 ∣ + ∣ x - 2 ∣ + ∣ x - 4 ∣}$

Question Number 209543 Answers: 1 Comments: 2

∫(dx/(x^4 +4))

$\int \frac{d x}{x^{4} + 4}$

Question Number 209484 Answers: 0 Comments: 0

∫_e^x ^e^2 ((1/(2+ln t)) )dt =?

$\underset{e^{x}}{\int^{e^{2}}} (\frac{1}{2 + \ln t}) dt = ?$

Question Number 209393 Answers: 1 Comments: 3

∫_0 ^(π/2) ((ln(tanx))/(1+tanx))dx

$\int_{0}^{\frac{π}{2}} \frac{l n (t a n x)}{1 + t a n x} d x$

Question Number 209353 Answers: 1 Comments: 0

Question Number 209332 Answers: 3 Comments: 0

Question Number 209217 Answers: 2 Comments: 0

calculate : I= ∫_(0 ) ^( ∞) (( tan^( −1) (x))/((1 + x^( 2) )^( 2) )) dx = ?

$c a l c u l a t e :$ $I = \int_{0}^{\infty} \frac{{t a n}^{- 1} (x)}{{(1 + x^{2})}^{2}} d x = ?$

Question Number 208900 Answers: 0 Comments: 0

Does anyone know of an intuition behind the integral form of the remainder in Taylor′s theorem?

$D o e s a n y o n e k n o w o f a n i n t u i t i o n$ $b e h i n d t h e i n t e g r a l f o r m o f t h e$ $r e m a i n d e r i n {T a y l o r}^{'} s t h e o r e m ?$

Question Number 208871 Answers: 3 Comments: 0

L=∫_0 ^1 (√((4−3x)/(4+5x)))dx

$L = \int_{0}^{1} \sqrt{\frac{4 - 3 x}{4 + 5 x}} d x$

Question Number 208842 Answers: 1 Comments: 1

does the rule of odd and even functions can be applied with improper integration? I=∫_(−∞) ^∞ xe^(−x^2 ) dx while f(x)= xe^(−x^2 ) is odd then I =0

$d o e s t h e r u l e o f o d d a n d e v e n f u n c t i o n s$ $c a n b e a p p l i e d w i t h i m p r o p e r i n t e g r a t i o n ?$ $I = \int_{- \infty}^{\infty} {x e}^{- x^{2}} d x$ $w h i l e f (x) = {x e}^{- x^{2}} i s o d d$ $t h e n I = 0$

Question Number 208805 Answers: 0 Comments: 3

Integrate: (xdz − zdx) − a^2 (2xzdz − z^2 dx) + 2x^3 = 0

$Integrate :$ $(xdz - zdx) - a^{2} (2 xzdz - z^{2} dx) + {2 x}^{3} = 0$

Question Number 208791 Answers: 0 Comments: 1

If ∫ (dx/(x^3 (1 + x^6 )^(2/3) )) = xf(x).(1 + x^6 )^(1/3) + C where C is constant of integration then find f(x).

$If \int \frac{d x}{x^{3} {(1 + x^{6})}^{\frac{2}{3}}} = x f (x) . {(1 + x^{6})}^{\frac{1}{3}} + C$ $where C is constant of integration then$ $find f (x) .$

Question Number 208733 Answers: 1 Comments: 0

2∫_(1/3) ^1 ((x(√(−3x^2 +4x−1)))/(7x^2 −4x+1))dx=? Exact solution needed.

$2 \underset{\frac{1}{3}}{\int^{1}} \frac{x \sqrt{- 3 x^{2} + 4 x - 1}}{7 x^{2} - 4 x + 1} d x = ?$ $Exact solution needed .$

Question Number 208692 Answers: 1 Comments: 0

∫_0 ^(π/2) xln sin x dx=?

$\underset{0}{\int^{π / 2}} x \ln \sin x d x = ?$

Question Number 208661 Answers: 1 Comments: 0

⇃

$⇃ \underset{―}{}$

Question Number 208652 Answers: 1 Comments: 0

Pg 4 Pg 5 Pg 6 Pg 7 Pg 8 Pg 9 Pg 10 Pg 11 Pg 12 Pg 13

Contact: info@tinkutara.com