Question and Answers Forum

All Questions      Topic List

Coordinate Geometry Questions

Previous in All Question      Next in All Question      

Previous in Coordinate Geometry      Next in Coordinate Geometry      

Question Number 157991 by zainaltanjung last updated on 30/Oct/21

$$$$$$$$$$\mathrm{Length}\mathrm{side}\mathrm{of}\mathrm{hexagonal}\mathrm{above}\mathrm{is}=12$$$$\mathrm{cm}.\mathrm{Find}{\mathrm{it}}^{\prime }\mathrm{s}\mathrm{total}\mathrm{area}$$$$$$

Answered by Rasheed.Sindhi last updated on 30/Oct/21

$$Composedof6equilateraltriangles$$$$Areaofeachtriangle$$$$=\sqrt{18.6.6.6}=6.6\sqrt{3}$$$$Totalareaofhexagon$$$$=6.6.6\sqrt{3}=216\sqrt{3}{\mathrm{cm}}^2$$

Commented by zainaltanjung last updated on 30/Oct/21

$${\mathrm{it}}^{\prime }\mathrm{s}\mathrm{true}\mathrm{brother}.$$$$\mathrm{The}\mathrm{total}\mathrm{Area}=$$$$6\times \frac{1}{2}\times 12\times 12\times \sin 60°$$$$=3\times 144\times \frac{1}{2}\sqrt{3}=216\sqrt{3}$$$$$$$$$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com