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Question Number 19638 by Tinkutara last updated on 13/Aug/17
LetP(x)isapolynomialsuchthatP(1)=1,P(2)=2,P(3)=3,andP(4)=5.FindthevalueofP(6).
Answered by ajfour last updated on 13/Aug/17
letP(x)=ax3+bx2+cx+dP(1)=1,⇒a+b+c+d=1P(2)=2,⇒8a+4b+2c+d=2P(3)=3,⇒27a+9b+3c+d=3P(4)=5,⇒64a+16b+4c+d=5⇒37a+7b+c=219a+5b+c=17a+3b+c=1⇒18a+2b=112a+2b=0⇒6a=1ora=16b=−1,c=1−3b−7a⇒c=1+3−76=176d=1−a−b−c=1−16+1−176=−1P(x)=x36−x2+17x6−1P(6)=36−36+17−1=16.
Commented by Tinkutara last updated on 13/Aug/17
ThankyouverymuchSir!
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