Let f(x)= sin^3 (2x) for −(π/4)≤x≤(π/4) then Df^(−1) ((1/8))=(a/(b(√b))) so { ((a=?)),((b=?)) :}


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Question Number 161114 by cortano last updated on 12/Dec/21
$Let f(x)= sin^3 (2x) for −(π/4)≤x≤(π/4) then Df^(−1) ((1/8))=(a/(b(√b))) so { ((a=?)),((b=?)) :}$
$L e t f (x) = \sin^{3} (2 x) f o r - \frac{π}{4} ⩽ x ⩽ \frac{π}{4}$ $t h e n {D f}^{- 1} (\frac{1}{8}) = \frac{a}{b \sqrt{b}} s o {\begin{cases} a = ? \\ b = ? \end{cases}$
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