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All Questions Topic List |
LimitsQuestion and Answers: Page 10 |
Question Number 193976 Answers: 2 Comments: 0
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Question Number 193874 Answers: 1 Comments: 0
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Question Number 193863 Answers: 2 Comments: 0
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lim_(x→0) ((1−(1/2)x^2 −cos ((x/(1−x^2 ))))/x^4 ) =?
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Question Number 193819 Answers: 1 Comments: 0
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lim_(x→0) cos ((((Π/3)+x)/x))
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Question Number 193803 Answers: 1 Comments: 0
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lim_(x→2) (((√(11−x)) cos ((π/(x−2))))/(cot (x−2)))=?
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Question Number 193596 Answers: 2 Comments: 0
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Question Number 193563 Answers: 3 Comments: 0
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Question Number 193540 Answers: 0 Comments: 0
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Question Number 193532 Answers: 2 Comments: 0
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lim_(x→2) ((1−cos πx)/((2−x)^2 )) =?
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Question Number 193408 Answers: 1 Comments: 0
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Question Number 193328 Answers: 1 Comments: 0
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f(x)= { ((((x^2 −x)/(x^2 −1)) ; x≠1)),((2x+1; x=1)) :}
thene find lim_(x→1) f(x)=?
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Question Number 193248 Answers: 1 Comments: 0
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L= lim_( x→0) (( sin(x )−arcsin(x))/(tan(x)− arctan(x)))=?
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Question Number 193236 Answers: 2 Comments: 0
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Question Number 193117 Answers: 3 Comments: 0
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lim_(x→0) (cosx)^(1/x)
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Question Number 192969 Answers: 2 Comments: 1
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Question Number 192867 Answers: 1 Comments: 0
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derivate of csc(2x) by definition
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Question Number 192846 Answers: 1 Comments: 0
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lim_(h→0) ((3h)/( ((3h+x))^(1/5) −(x)^(1/5) ))=?
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Question Number 192841 Answers: 1 Comments: 0
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Question Number 192652 Answers: 2 Comments: 0
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lim_(x→0) ((1−(√(cos(x))))/(1+cos((√x))))
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Question Number 192651 Answers: 2 Comments: 0
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lim_(x→0) ((2−(√(cos(x)))−cos(x))/x^2 )
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Question Number 192650 Answers: 2 Comments: 0
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lim_(x→0) ((x−sen(x))/(tan^3 (x)))
without lhopital rule
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Question Number 192646 Answers: 1 Comments: 0
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lim_(x⇒3) (√((x^2 −4x+3)/(x−3)))
find the limit
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Question Number 192639 Answers: 2 Comments: 0
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lim_(x⇒∝ ) ((3x^3 +3x^2 +1)/(5x^3 +4x^2 +x))
find the limit
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lim_(x⇒∝ ) ((3x^3 +3x^2 +1)/(5x^3 +4x^2 +x))
find the limit
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Question Number 192617 Answers: 2 Comments: 0
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Question Number 192616 Answers: 0 Comments: 0
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Question Number 192573 Answers: 0 Comments: 0
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solve;
lim_(x→0) x^2 tan(((sinπx)/(2x)))
solution
let L=lim_(x→0) x^2 tan(((sinπx)/(2x)))
since sinx∼x−(x^3 /6)
L=lim_(x→0) x^2 tan(((πx)/(2x))−((π^3 x^3 )/(12x)))
L=lim_(x→0) x^2 tan((π/2)−((π^3 x^2 )/(12)))
since tan((π/2)−x)=(1/(tanx))
L=lim_(x→0) (x^2 /(tan(((π^3 x^2 )/(12)))))
L=lim_(x→0) (((π^3 x^2 )/(12))/(tan(((π^3 x^2 )/(12))))) ((12)/π^3 )
L=((12)/π^3 )lim_(x→0) (((π^3 x^2 )/(12))/(tan(((π^3 x^2 )/(12)))))
since lim_(x→0) (x/(tanx))=1
L=((12)/π^3 ) ∙1=((12)/π^3 )
solved by HY a.k.a senestro
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