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LogarithmsQuestion and Answers: Page 7

Question Number 147108 Answers: 2 Comments: 0

Question Number 146849 Answers: 1 Comments: 1

Question Number 145829 Answers: 1 Comments: 0

Question Number 145437 Answers: 0 Comments: 0

original length of the iron rod=175.65 % increase=6(1/3)%×175.65 =((19)/3)×(1/(100))×175.65 =((19×175.65)/(3×100))=((3337.35)/(300))=11.1245 new length=original length+increased length =175.65+11.1245 =186.7745cm solution by CASIO.....

$o r i g i n a l l e n g t h o f t h e i r o n r o d = 175.65$ $% i n c r e a s e = 6 \frac{1}{3} % \times 175.65$ $= \frac{19}{3} \times \frac{1}{100} \times 175.65$ $= \frac{19 \times 175.65}{3 \times 100} = \frac{3337.35}{300} = 11.1245$ $n e w l e n g t h = o r i g i n a l l e n g t h + i n c r e a s e d l e n g t h$ $= 175.65 + 11.1245$ $= 186.7745 c m$ $s o l u t i o n b y C A S I O . . . . .$

Question Number 145108 Answers: 1 Comments: 0

Question Number 145071 Answers: 1 Comments: 0

log _(((x/2))) (x+2) = 1+ log _x (4−x) x=?

$\log_{(\frac{x}{2})} (x + 2) = 1 + \log_{x} (4 - x)$ $x = ?$

Question Number 145067 Answers: 1 Comments: 0

log _3 (x+1) =log _4 (x+8) x=?

$\log_{3} (x + 1) = \log_{4} (x + 8)$ $x = ?$

Question Number 144504 Answers: 0 Comments: 0

for what values of b is ln(a−b)ln(a+b)≤ln^2 a Note: 0≤b<a

$f o r w h a t v a l u e s o f b i s$ $l n (a - b) l n (a + b) ⩽ {l n}^{2} a$ $N o t e : 0 ⩽ b < a$

Question Number 143812 Answers: 1 Comments: 0

log _a (ax).log _x (ax)=log _a^2 ((1/a)) a>0 , a≠1 . So x = ?

$\log_{a} (ax) . \log_{x} (ax) = \log_{a^{2}} (\frac{1}{a})$ $a > 0, a \neq 1 . So x = ?$

Question Number 143811 Answers: 1 Comments: 0

{ ((5(log _y (x)+log _x (y))=26)),(( xy = 64)) :}then x^2 +y^2 +xy =?

${\begin{cases} 5 (\log_{y} (x) + \log_{x} (y)) = 26 \\ xy = 64 \end{cases} then$ $x^{2} + y^{2} + xy = ?$

Question Number 143475 Answers: 1 Comments: 1

evaluate; ((((√7))^(log64) −(3)^(log_(24) 8) )/((log _2 8−log _(1/4) 64)((1/(log _4 ((1/(64))))))))

$e v a l u a t e;$ $\frac{{(\sqrt{7})}^{\log 64} - {(3)}^{\log_{24} 8}}{(\log_{2} 8 - \log_{\frac{1}{4}} 64) (\frac{1}{\log_{4} (\frac{1}{64})})}$

Question Number 145524 Answers: 1 Comments: 0

What is the argument of the complex numbers below (i) z = 1+e^((π/6)i) (ii) z = 1 −e^((π/6)i)

$What is the argument of the complex numbers below$ $(i) z = 1 + e^{\frac{π}{6} i}$ $(ii) z = 1 - e^{\frac{π}{6} i}$

Question Number 142755 Answers: 1 Comments: 2

log_3 x^3 +log_2 x^2 =((2lg6)/(lg2))+1 find x

$\log_{3} x^{3} + \log_{2} x^{2} = \frac{2 \lg 6}{\lg 2} + 1 find x$

Question Number 141365 Answers: 1 Comments: 0

log _(9/4) ((1/(2(√3)))(√(6−(1/(2(√3)))(√(6−(1/(2(√3)))(√(6−(1/(2(√3)))(√(...))))))))) =?

$\log_{\frac{9}{4}} (\frac{1}{2 \sqrt{3}} \sqrt{6 - \frac{1}{2 \sqrt{3}} \sqrt{6 - \frac{1}{2 \sqrt{3}} \sqrt{6 - \frac{1}{2 \sqrt{3}} \sqrt{. . .}}}}) = ?$

Question Number 140730 Answers: 1 Comments: 0

If equation 2log (x+3)=log ax has only one solution. find the value of a.

$If equation 2 \log (x + 3) = \log ax$ $has only one solution . find the$ $value of a .$

Question Number 140680 Answers: 1 Comments: 0

log _((x+2)) (7x^2 −x^3 )−log _(1/(x+2)) (x^2 −3x)≥ log _((√(x+2)) ) ((√(5−x)) )

$\log_{(x + 2)} ({7 x}^{2} - x^{3}) - \log_{\frac{1}{x + 2}} (x^{2} - 3 x) ⩾ \log_{\sqrt{x + 2}} (\sqrt{5 - x})$

Question Number 138091 Answers: 2 Comments: 0

If 3^((log _3 7)^x ) = 7^((log _7 3)^x ) , then the value of x will be …

$I f 3^{{(\log_{3} 7)}^{x}} = 7^{{(\log_{7} 3)}^{x}}, t h e n t h e$ $v a l u e o f x w i l l b e \dots$

Question Number 137764 Answers: 1 Comments: 0

If log_2 3=a and log_3 7=b, express log_(42) 56 in terms of a and b

$If \log_{2} 3 = a and \log_{3} 7 = b, express$ $\log_{42} 56 in terms of a and b$

Question Number 136256 Answers: 1 Comments: 0

log _((x−2)) (10−3x) < 2

$\log_{(x - 2)} (10 - 3 x) < 2$

Question Number 136064 Answers: 1 Comments: 0

3^(log _2 (3^x −1)) = 2^(log _3 (2^x +1)) + 1

$3^{\log_{2} (3^{x} - 1)} = 2^{\log_{3} (2^{x} + 1)} + 1$

Question Number 134767 Answers: 0 Comments: 0

Question Number 134116 Answers: 1 Comments: 0

Question Number 133936 Answers: 2 Comments: 0

log _(x+8) (x^2 −3x−4) < 2.log _((4−x)^2 ) (∣x−4∣)

$\log_{x + 8} (x^{2} - 3 x - 4) < 2 . \log_{{(4 - x)}^{2}} (∣ x - 4 ∣)$

Question Number 133615 Answers: 2 Comments: 0

If log _4 (log _2 x)+log _2 (log _4 x)=2 then log _5 (√(x+(√x) +5)) = ?

$If \log_{4} (\log_{2} x) + \log_{2} (\log_{4} x) = 2$ $then \log_{5} \sqrt{x + \sqrt{x} + 5} = ?$

Question Number 131757 Answers: 0 Comments: 0

log3(√5)

$l o g 3 \sqrt{5}$

Question Number 131661 Answers: 1 Comments: 0

log _((√2) sin x) (1+cos x) = 2 −((2π)/3)≤x≤(π/3)

$\log_{\sqrt{2} \sin x} (1 + \cos x) = 2$ $- \frac{2 π}{3} ⩽ x ⩽ \frac{π}{3}$

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